2025 IJMB chemistry paper 3

QUESTION 1

Given Data:
Solution A: H₂SO₄ = 2.45 g dm⁻³
Solution B: Na₂CO₃.xH₂O = 1.43 g dm⁻³
Volume of B pipetted = 25 cm³
Indicator: Methyl orange

Reaction:
Na₂CO₃ + H₂SO₄ → Na₂SO₄ + CO₂ + H₂O


(b) CALCULATIONS

(i) Mass concentration of A
= 2.45 g dm⁻³


(ii) Molar concentration of A
Molar mass of H₂SO₄ = 98 g/mol

C = 2.45 / 98
= 0.025 mol dm⁻³


(iii) Moles of H₂SO₄ used
Volume = 25 cm³ = 0.025 dm³

n = C × V
= 0.025 × 0.025
= 6.25 × 10⁻⁴ mol


(iv) Moles of Na₂CO₃.xH₂O used
Ratio = 1 : 1

= 6.25 × 10⁻⁴ mol


(v) Molar concentration of B
C = n / V
= (6.25 × 10⁻⁴) / 0.025
= 0.025 mol dm⁻³


(vi) Molar mass of Na₂CO₃.xH₂O

Mass in 100 cm³ = 1.43 × 0.1 = 0.143 g

M = 0.143 / (6.25 × 10⁻⁴)
= 228.8 g/mol


(vii) Value of x

106 + 18x = 228.8
18x = 122.8
x = 6.82 ≈ 7

Na₂CO₃.7H₂O

© WHY METHYL ORANGE IS USED

  • The reaction is between a strong acid (H₂SO₄) and a weak base (Na₂CO₃)
  • The equivalence point lies in the acidic range (pH 3–5)
  • Methyl orange changes colour within pH 3.1–4.4, suitable for endpoint
  • Phenolphthalein is unsuitable because it changes in alkaline range (8.3–10) and gives a false endpoint

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QUESTION 2 — QUALITATIVE ANALYSIS

A1: LEAD TRIOXONITRATE(V) Pb(NO₃)₂

(a) Confirmatory tests for Pb²⁺

  1. Add dilute H₂SO₄
    Observation: White precipitate (PbSO₄)
    Inference: Pb²⁺ present

  2. Add dilute HCl
    Observation: White precipitate (PbCl₂), soluble on heating and reappears on cooling
    Inference: Pb²⁺ confirmed

Alternative strong test:
Add KI → yellow precipitate of PbI₂


(b) Tests for NO₃⁻

  1. Brown ring test
    Observation: Brown ring at interface
    Inference: Nitrate ion present

  2. Copper + conc H₂SO₄ test
    Observation: Brown gas (NO₂) formed
    Inference: Nitrate confirmed

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A2: ACETOPHENONE (C₆H₅COCH₃)

(a) Physical properties

  • Colourless liquid
  • Sweet aromatic smell
  • Slightly oily

(b) Solubility

(i) Water
Slightly soluble, cloudy mixture

(ii) Dilute HCl
Slight solubility, no major reaction

(iii) Dilute NaOH
Insoluble, no reaction


© Functional group tests

  1. Flame test
    Observation: Smoky/sooty flame
    Inference: Aromatic compound present

  2. NaHCO₃ test
    Observation: No gas evolved
    Inference: No carboxylic acid group

  3. 2,4-DNPH test
    Observation: Orange/yellow precipitate
    Inference: Carbonyl group (C=O) present

  4. Iodoform test (IMPORTANT)
    Observation: Yellow precipitate of CHI₃
    Inference: Methyl ketone present (acetophenone confirmed)

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FINAL CONCLUSION

  • Solution A is a strong acid (H₂SO₄)
  • Solution B is hydrated sodium carbonate (Na₂CO₃.7H₂O)
  • Acetophenone is an aromatic methyl ketone confirmed by DNPH and iodoform tests
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